• New article from the Springfield Shopper: Season 36 News: More Preview Images and Details for “O C’mon All Ye Faithful” have been released!
  • Wikisimpsons needs more Featured Article, Picture, Quote, Episode and Comprehensive article nominations!
  • Wikisimpsons has a Discord server! Click here for your invite! Join to talk about the wiki, Simpsons and Tapped Out news, or just to talk to other users.
  • Make an account! It's easy, free, and your work on the wiki can be attributed to you.
TwitterFacebookDiscord

Difference between revisions of "AstraZeneca Spuckler"

Wikisimpsons - The Simpsons Wiki
(Created page with "{{Character |name = AstraZeneca Spuckler |image = |gender = |hair = |age = babe |status = Alive |job = |relatives = Spuckler family |appearance = "Pretty Whittle Lia...")
 
 
Line 4: Line 4:
 
|gender =  
 
|gender =  
 
|hair =  
 
|hair =  
|age = babe
+
|age =  
 
|status = Alive
 
|status = Alive
 
|job =  
 
|job =  
Line 15: Line 15:
  
 
== History ==
 
== History ==
[[Brandine Spuckler]] (temporarily living with the Simpsons) is missing [[Moderna Spuckler|Moderna]], AstraZeneca and twins [[Johnson & Johnson Spuckler|Johnson & Johnson]].
+
When [[Brandine Spuckler]] was living with the [[Simpson family]], she said that she was missing [[Moderna Spuckler|Moderna]], AstraZeneca and twins [[Johnson & Johnson Spuckler|Johnson & Johnson]].
 +
 
 +
== Behind the Laughter ==
 +
AstraZeneca's name is a reference to the {{W|Oxford–AstraZeneca COVID-19 vaccine}}.
  
 
== Appearances ==
 
== Appearances ==

Latest revision as of 16:23, July 30, 2022

AstraZeneca Spuckler
Character Information
Status:
Alive
Relatives: Spuckler family
First appearance: "Pretty Whittle Liar"


AstraZeneca Spuckler is a member of the Spuckler family.

History[edit]

When Brandine Spuckler was living with the Simpson family, she said that she was missing Moderna, AstraZeneca and twins Johnson & Johnson.

Behind the Laughter[edit]

AstraZeneca's name is a reference to the Oxford–AstraZeneca COVID-19 vaccine.

Appearances[edit]